Question
In a certain code language, βNβ is coded as β8β
and βUβ is coded as β11.5β then βRIGβ will be coded as ____ in the same code language.Solution
The positional value of the alphabet is divided by 2 and then one is added to it to obtain the code. The positional value of βNβ is 14, so N is coded as [(14 Γ· 2) + 1] = [7 + 1] = 8. The positional value of βUβ is 21, so U is coded as [(21 Γ· 2) + 1] = [10.5 + 1] = 11.5. Similarly, The positional value of βRβ is 18, so R is coded as [(18 Γ· 2) + 1] = [9 + 1] = 10. The positional value of βIβ is 9, so I is coded as [(9 Γ· 2) + 1] = [4.5 + 1] = 5.5. Β The positional value of βGβ is 7, so G is coded as [(7 Γ· 2) + 1] = [3.5 + 1] = 4.5. Therefore, βRIGβ is coded as β10, 5.5, 4.5β.
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