In a certain code language, ‘N’ is coded as ‘8’

Solution

The positional value of the alphabet is divided by 2 and then one is added to it to obtain the code. The positional value of ‘N’ is 14, so N is coded as [(14 ÷ 2) + 1] = [7 + 1] = 8. The positional value of ‘U’ is 21, so U is coded as [(21 ÷ 2) + 1] = [10.5 + 1] = 11.5. Similarly, The positional value of ‘R’ is 18, so R is coded as [(18 ÷ 2) + 1] = [9 + 1] = 10. The positional value of ‘I’ is 9, so I is coded as [(9 ÷ 2) + 1] = [4.5 + 1] = 5.5.   The positional value of ‘G’ is 7, so G is coded as [(7 ÷ 2) + 1] = [3.5 + 1] = 4.5. Therefore, “RIG” is coded as ‘10, 5.5, 4.5’.