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Sol: Let the number of boys be x. Then, number of girls = 2x ∴ x + 2x = 60 or x = 20 So, number of boys = 20 and number of girls = 40 Number of students behind Rohan in rank = 60 – 17 = 43 Number of girls ahead of Rohan in rank = 9 Number of girls behind Rohan in rank = 40 – 9 = 31 ∴ Number of boys behind Rohan in rank = 43 – 31 = 12
Statement: C < P > T = E < R; G > R > A < D
Conclusions:
I. T < G
II. G ≥ P
III. T > A
Statement: L ≥ M ≤ R = S; M > N ≥ P
Conclusions:
I. P ≤ M
II. L > N
Statements: D > E = K ≥ G = H ≥ I, F < J ≤ I
Conclusions:
I. G ≥ F
II. J ≤ K
III. E > F
Statements: K @M, L #M, L$W, W%X
Conclusions:
I.K%L
Statements: R < S = T ≤ U < X < V, W = J ≥ Z = V
Conclusions:
I. X > W
II. U ≤ Z
III. J ≥ X
Statements: B > K < Y, E > C ≥ O = Y
Conclusions:
I. C > B
II. E ≤ Y
III. E > K
IV. O ≥ K
...Statements: D ≤ R < E = F, W = B > A ≥ F
Conclusions:
I. E = W
II. D < B
Statement: P > Q ≥ R = S ≤ T < U
Conclusions: I. T > Q II. U < P
...Statements: D > E > F ≥ G = H; D ≤ I < J ≤ B; H ≤ K = M < L
Conclusions:
I. M ≥ I
II. H > I
III. L > F