Combined inequality : S > T ≥ U < V S > T ≥ U < VNo relationship can be established between T and V hence, conclusion I will not follow. S > T ≥ U < V∴ S > U. Hence, conclusion II will follow.
Statements: F > T = O > E < P ≤ X > H < M
Conclusion I: F ≥ E
II: X > E
Statements: R > S ≥ T = U < V ≤ W; X ≥ Y = Z < U = M ≥ N
Conclusions:
I. S ≥ M
II. T < X
III. W > N
Statements: L = T > V ≥ M = I; V < O ≤ U = S
Conclusions:
I. T < S
II. U > I
Statements: X ≥ W > O = F ≥ B ≥ J; M < A ≤ J
Conclusions:
I. M < B
II. O ≥ A
III. O < A
...Statements: R @ D, D $ J, J # M, M @ K
Conclusions: I. K # J II. D @ M III. ...
Statements : I @ L © R * A $ M
Conclusions :
I. R * M
II. A % L
III. A % I
Statements: G < H ≤ I, V ≥ W = G, R ≥ I = A
Conclusions :
I. R > G
II. A ≥ H
III. H ≤ R
Statements: P = Q ≥ S > U = Y, U ≤ R < T ≤ W < V
Conclusions:
I. V > Y
II. P ≥ R
III. T < Q
Statements: A ≥ B = C; D ≥ E > F; C > G; G ≥ D; F > H
Conclusion:
I. F < D
II. E > H
III. G ≥ E
Statement: F ≥ G > I > E ≤ P, E = S ≥ P
Conclusion: I. F ≥ P II. G > P
