Statements:Q = S > T > Z; T > Y = H < I
Conclusions: I. Z > H II. I > Z
Combined inequality: Q = S > T > Z & Q = S > T > Y = H < I & Z < T > Y = H < I Conclusion: I.Z < T > Y = H < I No relationship can be established betweenZ and H. Hence, conclusion I is not true. II.Z < T > Y = H < INo relationship can be established between I and Z. Hence, conclusion II is not true.
Which is not in relation to the database.
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calculate the complexity of the below recursive code
Int f(int n)
{
If(n
return 1;
return f(n/2)+f(n/2);
}
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