At what angle the hands of a clock are inclined at 25 minutes past 9?
Angle traced by hour hand 113/12 hours = 360/60 × `113/12` = 282 1/2 ⁰ Angle traced by minute hand in 25 minutes = (360/60 × 25) = 1500` ` Required angle = 282 `1/2` ⁰ - 1500= 132 (1/2)0 Alternate method: θ=11/2 M-30H= 11/2×25-30×9=137.5-270=132.5
(1560.23 ÷ 25.98) + (768.32 ÷ 23.9) + 1814.11 = ?
(10.98% of 499.99) - 4.998 = √?
( 1728)1/3 × 10.11 × 3.97 ÷ 8.32 = ? + 15.022
(11.98% of 449.99) - 3.998 = √?
`sqrt(224.991)` + (3.81008)2 = ?`-:` `1/6.0001`
` `
(519.98 + ?) ÷ 13.01 = √440 + 20.0
? + 144.99 – 120.01 = 25.01 × 6.98
19.92 × (52.065/260.07) × (45.09% of 359.87) =?
(9.013 – 15.04) = ? + 9.98% of 5399.98
21.11 × 4.98 + 22.03 × 4.12 – 31.95 + 95.9 × 3.02 =?
