Question
Simplify: 15cos 41° cosec 49° - 6tan 55° tan
35°Solution
15cos 41° cosec 49° - 6tan 55° tan 35° = 15cos 41° cosec (90° - 41°) - 6tan (90° - 35°) tan 35° Using, cosec (90° - A) = sec A and tan (90° - A) = cot A = 15cos 41° sec 41° - 6cot 35° tan 35° Since, sec A is reciprocal of cos A and cot A is reciprocal of tan A. = 15 - 6 = 9
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