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    Question

    Solve for x in the interval [0, 2π]: 2 sin²x + 3 sinx

    - 2 = 0.
    A x = π/6, 5π/6 Correct Answer Incorrect Answer
    B x = π/4, 3π/4 Correct Answer Incorrect Answer
    C x = π/3, 4π/3 Correct Answer Incorrect Answer
    D None of these Correct Answer Incorrect Answer

    Solution

    Let sin x = y.  Then, 2y² + 3y - 2 = 0.  Solving, we get y = -2 or y = 1/2.  Thus, sin x = 1/2 gives x = π/6, 5π/6. Correct answer: a

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