Question
Solve for x in the interval [0, 2π]: 2 sin²x + 3 sinx
- 2 = 0.Solution
Let sin x = y. Then, 2y² + 3y - 2 = 0. Solving, we get y = -2 or y = 1/2. Thus, sin x = 1/2 gives x = π/6, 5π/6. Correct answer: a
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