Question
In a triangle ABC, if 5∠A = 3∠B = 15∠C, then find the
value of cosA + sin(C + 10 ° )Solution
Given, 5∠A = 3∠B = 15∠C
Or, ∠A:∠B:∠C = (1/5):(1/3):(1/15) = 3:5:1
Let ∠A, ∠B and ∠C be '3x', '5x' and 'x', respectively
Therefore, 3x + 5x + x = 180 o (sum of the interior angles of a triangle is 180 o )
Or, 9x = 180 o
Or, x = 20 o
Therefore, cosA + sin(C + 10 o ) = cos60 o + sin30 o = (1/2) + (1/2) = 1
Simplify:
6x + 8y - [(12x + 6y) - (4x + 3y) + 2y] - 4xIf 9x2 + 16y2 = 24xy, then find the ratio of ‘x’ and ‘y’, respectively.
- Suppose [a + (1/16a)] = 3, then the value of [16a³ + (1/256a³)] is:
If, 6x + y = 20, and 2xy = 32, and 6x > y, then find the value of 216x³ – y³.
If x + 1/x = 2, find x⁷ + 1/x⁷.
(x – 6) 2 + (y + 2) 2 + (z – 4) 2 = 0, then find the value of 4x - 3y + z.
Three cubes of metal whose edges are 3cm, 4cm and 5cm. respectively are melted and a single cube is formed. What is the length of the edge of the newly ...
A number is increased by 20%, and the resulting number is decreased by 20%. If the initial number is ₹x, the final number is ₹2880. What is the valu...
Relevant for Exams:
