Question
If (sin A + cos A) = √3 cos (90° - A), then find the
value of cot A.Solution
We have, (sin A + cos A) = √3 cos (90° - A)
Or, (sin A + cos A) = √3 sin A (since, cos (90° - A) = sin A)
Or, cos A = (√3 - 1) sin A
Or, {(cos A)/(sin A)} = (√3 - 1)
So, cot A = (√3 - 1)
Hence, option a.
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