Question
If sin (a + b) = (√3/2) and cos (a – b) = (√3/2),
then find sin a.Solution
Given: sin (a + b) = (√3/2) and cos (a – b) = (√3/2)
So, sin (a + b) = sin 60 o
Or, a + b = 60 o ………. (I)
And cos (a – b) = cos 30 o
Or, (a – b) = 30 o ……… (II)
On adding equation (I) and (II), we have;
2a = 90 o
Or, a = 45 o
So, required value = sin 45 o = (1/√2)
I. 6x² - 23x + 7 = 0
II. 6y² - 29y + 9 = 0
I. 2x² + 15 x - 27 = 0
II. 3 y² + 25 y - 18 = 0
I. 2x² - 11x + 12 = 0
II. 12y² + 29y + 15 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0
I. 6x² - 49x + 99 = 0
II. 5y² + 17y + 14 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 41x + 400 = 0
Equation 2: y² - 41y + 420 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
I. 2x2 + 3x - 9 = 0
II. 3y2 - y - 10 = 0
I. 104x² + 9x - 35 = 0
II. 72y² - 85y + 25 = 0