Question
If sin (a + b) = (√3/2) and cos (a – b) = (√3/2),
then find sin a.Solution
Given: sin (a + b) = (√3/2) and cos (a – b) = (√3/2)
So, sin (a + b) = sin 60 o
Or, a + b = 60 o ………. (I)
And cos (a – b) = cos 30 o
Or, (a – b) = 30 o ……… (II)
On adding equation (I) and (II), we have;
2a = 90 o
Or, a = 45 o
So, required value = sin 45 o = (1/√2)
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c) ...
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c) Oxidation
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