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      Question

      If A, B and C are angles of triangle, then sin2A + sin2B

      + sin2C– 2cosA cosB cosC
      A 1 Correct Answer Incorrect Answer
      B 2 Correct Answer Incorrect Answer
      C 4 Correct Answer Incorrect Answer

      Solution

      Let A = B = 45º, C = 90º
      then, sin2A, + sin2B + sin2C – 2 cosA cosB cosC
      = (1/√2) 2 + ( 1/√2) 2 + 1 – 0 (as cosC = 0)
      = 1/2 + 1/2 + 1 = 2

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