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    Question

    If A, B and C are angles of triangle, then sin2A + sin2B

    + sin2CтАУ 2cosA cosB cosC
    A 1 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 4 Correct Answer Incorrect Answer

    Solution

    Let A = B = 45┬║, C = 90┬║
    then, sin2A, + sin2B + sin2C тАУ 2 cosA cosB cosC
    = (1/тИЪ2) 2 + ( 1/тИЪ2) 2 + 1 тАУ 0 (as cosC = 0)
    = 1/2 + 1/2 + 1 = 2

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