Question

    If A, B and C are angles of triangle, then sin2A + sin2B

    + sin2C– 2cosA cosB cosC
    A 1 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 4 Correct Answer Incorrect Answer

    Solution

    Let A = B = 45º, C = 90º
    then, sin2A, + sin2B + sin2C – 2 cosA cosB cosC
    = (1/√2) 2 + ( 1/√2) 2 + 1 – 0 (as cosC = 0)
    = 1/2 + 1/2 + 1 = 2

    Practice Next

    Relevant for Exams: