Question
Given that 'θ' is an angle less than 120 °
, what is the value of 'θ' if it satisfies the equation 3cos 2 θ = 2 + sin 2 θ.Solution
Given, 3cos 2 θ = 2 + sin 2 θ
3cos 2 θ - sin 2  θ = 2
3cos 2 θ - (1 - cos 2  θ) = 2
4cos 2 θ = 3
cos 2 θ = (3/4)
cosθ = √3/2 (Since, in options maximum value of 'θ' is 90 o  therefore, we will take the positive root only)
cosθ = cos30 o
θ = 30 o
2660.03 ÷ 94.98 x 59.9 = ? + 20.32
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...
Find the approximate value of Question mark(?). No need to find the exact value.
(519.79 ÷ 10.03) × (47.98 ÷ 6) + √(63.94) × 4.04 = ?
...447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
1131.98 + ? – 1125.04 = 1364.93 – 1168.01
11.11% of 1800.89 + 34.89 X 10.99 - 500.50 = ?
(3/7 of 1049.88 + 44.95% of 799.79) ÷ (√168.89 + 24.77% of 400.11) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
If a:(b+c) =3:9 and c:(a+b) =10:14 then find the value of b:(a+c)?
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