Question
If 4cos2x - 3 = 0, and (0° > x > 90°),
then find the value of 'x'.Solution
Given, 4cos2x - 3 = 0
Or, 4cos2x = 3
So, cos2x = (3/4)
Or, cosx = (√3/2)
Or, cosx = cos 30o
So, x = 30o
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