Question
Which of the following is true when x = SinA + CosA and y = SecA + CosecA?
Solution
x = SinA + CosA       … (1) y = SecA + CosecA =1/cosA +1/sinA =(sinA+CosA)/SinA.CosA y = x/SinA.CosA       … (2) EQ (1) both sides squaring… x2=1+2sinA.CosA SinA.CosA =(x2-1)/2 Put the value in EQ (2). y =2x /(x2-1) yx2-y =2x y+2x =x2y.
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