Question
which of the following is equal to [(tan θ +secθ -1)/
(tanθ-secθ +1)] ÂSolution
[(tan θ +secθ -1)/ (tanθ-secθ +1)]        [sec2 θ- tan2 θ=1] = [ tan θ +secθ – (sec2 θ – tan2 θ)]/ (tan θ -sec θ+1) = (tan θ +sec θ) [(1-sec θ +tan θ)/ (tan θ-sec θ+1)] = tan θ +sec θ =sin θ / cos θ +1/cos θ = (1+sin θ)/cos θ
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