Question
Simplify: 14sin 33° sec 57° - 9tan 71° tan
19°Solution
14sin 33° sec 57° - 9tan 71° tan 19° = 14sin 33° sec (90° - 33°) - 9tan (90° - 19°) tan 19° Using, sec (90° - A) = cosec A and tan (90° - A) = cot A = 14sin 33° cosec 33° - 9cot 19° tan 19° Since, cosec A is reciprocal of sin A and cot A is reciprocal of tan A. = 14 - 9 = 5
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