Question
In ∆ PQR, S is the midpoint of QR. T is the midpoint
of line PS. Then, Area of ∆PTQ : Area of ∆ PQR isSolution
Let the area of the ∆ PQR = 100 Then the area of ∆ PSQ = 100/2 = 50 And the area of ∆ PQT = 50/2 = 25 Area of ∆PTQ : Area of ∆ PQR = 25 : 100 = 1 : 4
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