Question
In triangle ABC, the lengths of its sides are given as
AB = 8 cm, AC = 10 cm, and BC = 12 cm. Determine the length of the median drawn from vertex 'A' to the side BC.ÂSolution
If ABC is a triangle such that AB = 'c', BC = 'a' and AC = 'b', then length of median from 'A': = √[(2b2 + 2c2 - a2) ÷ 4] 
Here, AB = 8 cm, AC = 10 cm and BC = 12 cm Therefore, required length of median = √[(2 X 102 + 2 X 82 - 122) ÷ 4] = √[(200 + 128 - 144) ÷ 4] = √(184/4) = √46 cm Â
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