Question
The batting average for 40 innings of a cricket player
is 50 runs. His highest score exceeds his lowest score by 172 runs, If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player isSolution
let the score of lowest inning = x score of highest inning = x+172 avg of 38 innings = 48 total score of 38 innings = 48 × 38 = 1824 total score of 40 innings = 50 × 40 = 2000 x+x+172 = 2000 – 1824 2x+172 = 176 2x= 4 x=2 highest score of the player = 172+2 = 174
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