Question
In the given figure, AB ∥ QP, AB = x, PQ = x + 10, RB
= x/2, BP = x + 1. Find PQ.Solution
ATQ,
Given: AB∥PQ, so we use the Basic Proportionality Theorem:
Substituting values:
Multiply by 2 to remove the fraction:
2x(x+1)=x(x+10) Expand and simplify: x2 −8x=0 Factorize = (x−8)=0 Solve for x: x = 8 (since x=0 is not valid) Find PQ: PQ = x+10 = 8+10 = 18
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