Question
A ΔABC such that AB = 3 cm, BC = 2 cm and AC = 2.5
cm. ΔDEF similar to ΔABC. If EF = 4 cm then the perimeter of ΔDEF is-Solution
Given that, ΔDEF similar to ΔABC then (AB/BC) = (DE/EF) ⇒ (3/2) = DE/4 DE = 6 cm similarly, (BC/AC) = (EF/DF) ⇒ (2/2.5) = 4/DF then DF = 5 then perimeter of ΔDEF is = DE+EF+DF = 6 + 4 + 5 = 15 cm
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