Question
The sides of a triangle are 13 cm, 14 cm, and 15 cm.
What is the area of the triangle?Solution
We can use Heron’s formula to find the area of the triangle. First, find the semi-perimeter (s): s = (13 + 14 + 15) / 2 = 21 cm Now, use the formula for area: Area = √[s(s - a)(s - b)(s - c)] Area = √[21(21 - 13)(21 - 14)(21 - 15)] Area = √[21 × 8 × 7 × 6] Area = √[7056] Area = 84 cm² Correct Option: a) 84 cm²
I. 6x² + 37x + 45 = 0
II. 3y² - 11y + 6 = 0
I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
if x satisfies 3x² – 5x – 12 = 0, find the sum of reciprocals of roots.
I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
I. 2x2 - 5x - 33 =0
II. 2y2 + 5y - 25 = 0
Equation 1: x² - 180x + 8100 = 0
Equation 2: y² - 170y + 7225 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 41x² - 191x + 150 = 0
Equation 2: 43y² - 191y + ...
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
Roots of the quadratic equation 2x2 + x – 528 = 0 is
I. 4x² -  15x + 9 = 0
II. 20y² -  23y + 6 = 0
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