Question
Train 'A' is 300 meters long and crosses a pole in 15
seconds. It completely crosses Train 'B' (opposite direction) in 10 seconds. If Train 'B' is twice as long as Train 'A', how much distance does Train 'B' cover in 20 minutes?Solution
Speed of Train 'A' = 300 ÷ 15 = 20 m/s Length of Train 'B' = 2 × 300 = 600 meters Combined length of Train 'A' and 'B' = 300 + 600 = 900 meters Relative speed of Train 'B' w.r.t Train 'A' = 900 ÷ 10 = 90 m/s So, speed of Train 'B' = 90 − 20 = 70 m/s = 70 × (18/5) = 252 km/h Distance covered by Train 'B' in 20 minutes = 252 × (20/60) = 84 km
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