Question
A train travelling with a speed of 90 km/h can cross a
pole in 8 seconds. Find the time taken by the train to cross a 220 metres long platform if the speed of train is increased by 20%.Solution
Speed of train = 90 × 5/18 = 25 m/s Length of train = 25 × 8 = 220 metres Desired time = (220 + 90)/(1.20 × 25) = 14 seconds
More Trains Questions
I. 3x2 - 14x + 15 = 0
II. 15y2 - 34 y + 15 = 0
I. 2x2 + 5x + 2 = 0
II. 4y2 = 1
If x2Â - 3x - 18 = 0 and y2Â + 9y + 18 = 0, which of the following is true?
I. 12x2 - 55x + 63 = 0
II. 10y2 - 47y + 55 = 0
I. Â 3y2Â + 13y - 16 = 0
II. 3x2 – 13x + 14 = 0
I. 27x² + 120x + 77 = 0
II. 56y² + 117y + 36 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 38x + 352 = 0
Equation 2: y² - 38y + 312 = 0
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
I. 6x2 + 19x + 10 = 0
II. y2 + 10y + 25 = 0
