Question
A train of 175 metres is running at a speed of 72 km/h and
crosses a platform in 36 seconds. Determine the length of the platform.Solution
ATQ,
Let the length of the platform be ‘x’ metres
Speed of the train = 72 × (5/18) = 20 m/s
ATQ,
(x + 175) = 20 × 36
Or, (x + 175) = 720
Or, x = 720 - 175
Or, x = 545
Therefore, the length of the platform = 545 metres
What approximate value will replace the question mark (?) in the following?
√40...
13.99% of 399.99 ÷ 28.17 = ? ÷ 25.15
245.67 + 20.05² + ?³ = √961.89 * 34.02
? + 39.99 X 3.01 = √624.99 X 10.01% of 49.99
Find the approximate value of Question mark(?) for given equation.
(563.84 ÷ 11.92) × 15.08 + 244.95 = ? × 10.01
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
?2/3 = 33.33% of 107.99 + 45.45
480 ÷ 10 + 18 % of 160 + ? * 9 = 60 * √36
74.99 x 175.01 - 75.12 x 154.98 + + 39.98) x 3.98 = (785.01 + 265.01) x 1.99
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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