Start learning 50% faster. Sign in now
ATQ, Let the speed of the train be ‘x’ m/s. Length of the train = 6 × x = ‘6x’ metres So, length of the platform = (6x + 70) metres ATQ; (6x + 70 + 6x) ÷ 18 = x Or, 12x + 70 = 18x Or, 70 = 6x So, x = 11.67 Therefore, length of the platform = (11.67 × 6) + 70 = 140 metres
Which of the following options is the closest approximate value which will come in place of question mark (?) in the following equation?
26.52 ×...
(? + 6.063.03 ) ÷ 10.08 + 21.89 × 6.97 = 1979.97 ÷ 10.96
? = (7.11/2.12) + (10.88/4.09) + (45.12/11.98)
(20.98 ÷ 2.91) + (15.12 – 5.96) = ?
24.052 + 14.03 × 22.99 – 28.18 × 14.94= ?
25.02% of 460.02+?% of 300.02=295.21
72.8% of (215.69 + 189.38) - 5.97² + (3.01 of 7.8) = ? of (64.02 - 38.95)
70.14% of 799.95 - 240.12 = ? + 40.17% of 299.95
14, 27, 40, 53, 67, 79
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...