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    Question

    When the speed of a passenger train is increased by 5

    km/hr, then to cover a distance of 300 km it takes 2 hours less time. What is its initial speed (in km/hr)?
    A 10 Correct Answer Incorrect Answer
    B 20 Correct Answer Incorrect Answer
    C 25 Correct Answer Incorrect Answer
    D 30 Correct Answer Incorrect Answer

    Solution

      Alternate solution: Distance = time gap (product of speed)/ gap of speed  or 300 =  2 (x)(x+5)/5 or 750 =x(x+5)  or x(x+5) = 25*30  So the speed of train = 25kmph

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