Question
When the speed of a passenger train is increased by 5
km/hr, then to cover a distance of 300 km it takes 2 hours less time. What is its initial speed (in km/hr)?Solution
 Alternate solution: Distance = time gap (product of speed)/ gap of speed or 300 = 2 (x)(x+5)/5 or 750 =x(x+5) or x(x+5) = 25*30 So the speed of train = 25kmph
? = (597.98 ÷ (6.97 2.01 – 3.1)) × 12.9
1153, 1206, ?, 1326, 1393, 1464
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