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      Question

      A train with 10 compartments of equal length takes 20

      seconds to cross a pole and 28 seconds to cross a 160-metre-long platform. If 4 compartments of the train are removed, then how long would it take to cross a pole?
      A 14 seconds Correct Answer Incorrect Answer
      B 16 seconds Correct Answer Incorrect Answer
      C 12 seconds Correct Answer Incorrect Answer
      D 18 seconds Correct Answer Incorrect Answer
      E 10 seconds Correct Answer Incorrect Answer

      Solution

      Let the original length of the train = β€˜d’ metres
      Then, distance covered by the train in 20 seconds = β€˜d’ metres
      Distance covered by the train in 28 seconds = (d + 160) metres
      So, distance covered by the train in (28 – 20) = 8 seconds = (d + 160 – d) = 160 metres
      So, speed of the train = 160 Γ· 8 = 20 m/s
      So, original length of the train = 20 Γ— 20 = 400 metres
      After removing 4 compartments, length of the train = 400 Γ— (6/10) = 240 metres
      So, required time taken = 240 Γ· 20 = 12 seconds

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