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    Question

    A train with 10 compartments of equal length takes 20

    seconds to cross a pole and 28 seconds to cross a 160-metre-long platform. If 4 compartments of the train are removed, then how long would it take to cross a pole?
    A 14 seconds Correct Answer Incorrect Answer
    B 16 seconds Correct Answer Incorrect Answer
    C 12 seconds Correct Answer Incorrect Answer
    D 18 seconds Correct Answer Incorrect Answer
    E 10 seconds Correct Answer Incorrect Answer

    Solution

    Let the original length of the train = ‘d’ metres
    Then, distance covered by the train in 20 seconds = ‘d’ metres
    Distance covered by the train in 28 seconds = (d + 160) metres
    So, distance covered by the train in (28 – 20) = 8 seconds = (d + 160 – d) = 160 metres
    So, speed of the train = 160 ÷ 8 = 20 m/s
    So, original length of the train = 20 × 20 = 400 metres
    After removing 4 compartments, length of the train = 400 × (6/10) = 240 metres
    So, required time taken = 240 ÷ 20 = 12 seconds

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