Question
A train with 8 compartments of equal length takes 18
seconds to cross a pole and 24 seconds to cross a 150-metre-long platform. If 4 compartments of the train are removed, then how long would it take to cross a pole?Solution
Let the original length of the train = ‘d’ metres
Then, distance covered by the train in 18 seconds = ‘d’ metres
Distance covered by the train in 24 seconds = (d + 150) metres
So, distance covered in (24 – 18) = 6 seconds = (d + 150 – d) = 150 metres
So, speed of the train = 150 ÷ 6 = 25 m/s
So, original length of the train = 25 × 18 = 450 metres
After removing 4 compartments, length of the train = 450 × (4/8) = 225 metres
So, required time taken = 225 ÷ 25 = 9 seconds
- What will come in place of (?) in the given expression.
(18.5 × 2) + (3.5 × 4) = ? 22% of 560 + 34% of 2160 × 5/12 =? + 16% of 920
12(3/5) + 4(1/5) × 3(2/3) =?
464 + 181 +? = (154 × 25) - (15) 2 Â
What will come in the place of question mark (?) in the given expression?
(? ÷ 16) = (20 ÷ ?) X 20360 × 9 ÷ 3 + 120 + 900 ÷ 5 = ?
- Find the value of the expression:
40 + 5 – 7 × [16 + 9 – 3 × (27 – 13)] 
What will come in the place of question mark (?) in the given expression?
(72 × 6 ÷ 12) × 6 = ?
The value of 43-3× (4×6+12/3 ×6-4×5) +4?
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