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      Question

      A train with 8 compartments of equal length takes 18

      seconds to cross a pole and 24 seconds to cross a 150-metre-long platform. If 4 compartments of the train are removed, then how long would it take to cross a pole?
      A 7 seconds Correct Answer Incorrect Answer
      B 8 seconds Correct Answer Incorrect Answer
      C 9 seconds Correct Answer Incorrect Answer
      D 10 seconds Correct Answer Incorrect Answer
      E 11 seconds Correct Answer Incorrect Answer

      Solution

      Let the original length of the train = β€˜d’ metres
      Then, distance covered by the train in 18 seconds = β€˜d’ metres
      Distance covered by the train in 24 seconds = (d + 150) metres
      So, distance covered in (24 – 18) = 6 seconds = (d + 150 – d) = 150 metres
      So, speed of the train = 150 Γ· 6 = 25 m/s
      So, original length of the train = 25 Γ— 18 = 450 metres
      After removing 4 compartments, length of the train = 450 Γ— (4/8) = 225 metres
      So, required time taken = 225 Γ· 25 = 9 seconds

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