Question
A train with 8 compartments of equal length takes 18
seconds to cross a pole and 24 seconds to cross a 150-metre-long platform. If 4 compartments of the train are removed, then how long would it take to cross a pole?Solution
Let the original length of the train = βdβ metres
Then, distance covered by the train in 18 seconds = βdβ metres
Distance covered by the train in 24 seconds = (d + 150) metres
So, distance covered in (24 β 18) = 6 seconds = (d + 150 β d) = 150 metres
So, speed of the train = 150 Γ· 6 = 25 m/s
So, original length of the train = 25 Γ 18 = 450 metres
After removing 4 compartments, length of the train = 450 Γ (4/8) = 225 metres
So, required time taken = 225 Γ· 25 = 9 seconds
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