Question
800 metres long train crosses a man who is moving in the
same direction with a certain speed, in 40 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 800/20 = 40 m/sec Let the speed of the man be βsβ m/sec Relative speed of the train = (40 β s) m/sec According to the question, (40 β s) = 800/40 Or, s = 40 β 20 = 20 Therefore, speed of the man = 20 m/sec
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{84.03 + 39.99 β (168.12 Γ· 6.95 β 17.03 Γ 7.91)} = ?
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