Question
1280 metres long train crosses a man who is moving in
the same direction with a certain speed in 20 seconds. If the same train can cross a pole in 16 seconds with the same speed, then find the speed of the man.Solution
Let the speed of the man be ‘x’ m/sec. Speed of train = 1280/16 = 80 m/sec Relative speed of the train = (80 – x) m/sec According to the question, => (80 – x) = 1280/20 => x = 80 – 64 => x = 16 Therefore the speed of the man = 16 m/sec
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NPQR, OORQ, PNSP, ____, RLUN
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