Question
A 330 m long train crosses a platform thrice its length
in 2 min. Find the speed of the train. TYPE 2Solution
Speed of train = (Length of train + Length of Platform)/Required time Length of train = 330 m Crossing time of platform = 2 × 60 = 120 sec Length of platform = 330 × 3 = 990 m Let the speed of train be x. Speed of train = (330 + 990)/120 ⇒  x = 1320/120 = 11 m/s
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