Question
Train 'A' is 250 meters long and it crosses a pole in
10 seconds. It also crosses Train 'B' moving in the opposite direction in 10 seconds. If Train 'B' is twice as long as Train 'A', find the distance covered by Train 'B' in 24 minutes.Solution
Speed of Train 'A' = 250 ÷ 10 = 25 m/s Length of Train 'B' = 2 × 250 = 500 meters Combined length of Train 'A' and 'B' = 250 + 500 = 750 meters Relative speed of Train 'B' w.r.t Train 'A' = 750 ÷ 10 = 75 m/s So, speed of Train 'B' = 75 − 25 = 50 m/s = 50 × (18/5) = 180 km/h Distance covered by Train 'B' in 24 minutes = 180 × (24/60) = 72 km
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