Question
Train 'A' is 250 meters long and it crosses a pole in
10 seconds. It also crosses Train 'B' moving in the opposite direction in 10 seconds. If Train 'B' is twice as long as Train 'A', find the distance covered by Train 'B' in 24 minutes.Solution
Speed of Train 'A' = 250 ÷ 10 = 25 m/s Length of Train 'B' = 2 × 250 = 500 meters Combined length of Train 'A' and 'B' = 250 + 500 = 750 meters Relative speed of Train 'B' w.r.t Train 'A' = 750 ÷ 10 = 75 m/s So, speed of Train 'B' = 75 − 25 = 50 m/s = 50 × (18/5) = 180 km/h Distance covered by Train 'B' in 24 minutes = 180 × (24/60) = 72 km
What approximate value should replace the question mark?
12.45% of 640.20 − 60% of 2500 = ? − 9000.10
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What value should come in place of question mark (?) in the following question. (You need not to calcualte the exact value)
?/647 = 226/ ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
A, B & C have Rs.1550 together. If they divide the money in the ratio 1:3:1 respectively. Find the difference of amount received by B and C.
What approximate value should come in the place of (?) in the following questions?
∛(92.8 + √1025) * ? = 16.06% of 750
√1024.21 × √624.89 ÷ 4.98 + 11.99 × 4.01 = ?
√784 × 3 + (713.99 ÷ 6.98) = ?% of 619.99
11.11% of (123.45 + 234.56) + 10.01³ - (5.05 of 7.07) = ? of (88.88 - 33.33)
