Question
Two trains βAβ and βBβ started from station
βPβ and βQβ towards station βQβ and βPβ respectively at the same time. When they met after 14 hours, train βBβ has travelled 120 km more than train βAβ. Find the distance travelled by train βAβ in 12 hours if distance between both stations is 400 km.Solution
Let distance travelled by train βAβ at the time of meet = βxβ km So, distance travelled by train βBβ at the time of meet = βx + 120β km According to question; x + x + 120 = 400 => 2x = 280 => x = 140 Distance travelled by train βAβ in 14 hours = 140 km Speed of train βAβ = 140/14 = 10 km/h Distance travelled by train βAβ in 12 hours = 12 Γ 10 = 120 km
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