Question
Two trains 190 metres and 140 metres in length are
running towards each other on parallel tracks, one at the rate 60 km/hr and another at 48 km/hr. In how many seconds will they be clear of each other from the moment they meet?Solution
Required time = Sum of the lengths of trains / Relative speed Relative speed = 60 + 48 = 108 kmph = (108 × 5)/18 = 30 m/sec Required time = (190 + 140)/30 = 330/20 = 11 seconds
I. x2 - 11x + 24 = 0
II. y² - 5y + 6 = 0
I. 25p + 2(2p2 – 1) = 8(p + 5)
II. 8q2 + 35q – 78 = 0
I. 3q² -29q +18 = 0
II. 9p² - 4 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 41x + 400 = 0
Equation 2: y² - 41y + 420 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
If the roots of the quadratic equation 5x² + 4x + 6 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
...I. 15b2 + 26b + 8 = 0
II. 20a2 + 7a - 6 = 0
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
