Question
8 children and 6 women together can complete a piece of
work in 10 days and work done by a children in one day is one-third of the work done by a women in one day. If 5 children and 7 women started working and after 4 days 2 women left the work and 4 new children joined then, in how many more days will the work be completed:Â Â ÂSolution
 One day work of children = one-third of work done by women in one day Let efficiency of one women = W unit/day And efficiency of one child = C So, W = 3C Total work = (8C + 6 x 3C) × 10 =260C unit 5 children and 7 women started working for 4 days Total work done = (5C + 7 × 3C) × 4 = 104C Left work = 260C – 104C = 156C 2 women replace 4 children = (9C + 15C) = 24C Days required = 156C/24C = 6.5 days Â
10Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 8.5Â Â Â Â Â Â Â Â Â Â 16Â Â Â Â Â Â Â Â Â Â Â Â Â ?
...17Â Â Â Â Â ? Â Â Â Â Â 2142 Â Â Â Â Â Â 12852 Â Â Â Â Â Â 64260Â Â Â Â Â Â 257040
...19, 37, 65, 91, 127, 169
31                          16.5                       18                     �...
73920, 9240, ?, 220, 44, 11
56, 57, 49, 76, 12, ?
The following numbers form a series followed by a (?). Find the odd one out first and then find that what will come in place of the question mark (?) ac...
20 9 10 ? 29 71.5
...123   125   129   132   ?   145
13, 26, 104, ?, 13312, 425984
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