Question
2 men and 5 boys can together complete a work in 8
days. 3 men and 4 boys can together complete the same work in 6 days. Find the time taken by 7 boys together to complete the entire work.Solution
Let the efficiency of a boy be 'B' units/day and the efficiency of a man be 'M' units/day we have, (2M + 5B) X 8 = (3M + 4B) X 6 Or, 16M + 40B = 18M + 24B Or, 16B = 2M So, B:M = 1:8 So, let B = '1a' and M = '8a' Total work = (2 X 8a + 5 X 1a) X 8 = '168a' units So, time taken by 7 boys together to complete the work = 168a ÷ (7 X 1a) = 24 daysÂ
Statements
Only a few A is B
No B is C
Only a few C is D
Some D is E
Conclusions:
I). Â No A is C
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All N are M Â
Only M is D. Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
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Some papers are not books.
All books are pencils.
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