Question
A can complete a piece of work in 12 days and B can complete it in 18 days. They work together for 4 days and then B leaves. In how many more days will A finish the remaining work?
Solution
ATQ, Aβs 1βday work = 1/12 Bβs 1βday work = 1/18 Together in 1 day: = 1/12 + 1/18 LCM(12,18) = 36 = 3/36 + 2/36 = 5/36 Work done in 4 days = 4 Γ 5/36 = 20/36 = 5/9 Remaining work = 1 β 5/9 = 4/9 Now only A works: Time = (remaining work) Γ· (Aβs 1βday work) = (4/9) Γ· (1/12) = (4/9) Γ 12 = 48/9 = 16/3 days Answer: A will take 16/3 days more.
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