Question
A can complete a piece of work in 12 days and B can
complete it in 18 days. They work together for 4 days and then B leaves. In how many more days will A finish the remaining work?Solution
ATQ, A’s 1‑day work = 1/12 B’s 1‑day work = 1/18 Together in 1 day: = 1/12 + 1/18 LCM(12,18) = 36 = 3/36 + 2/36 = 5/36 Work done in 4 days = 4 × 5/36 = 20/36 = 5/9 Remaining work = 1 − 5/9 = 4/9 Now only A works: Time = (remaining work) ÷ (A’s 1‑day work) = (4/9) ÷ (1/12) = (4/9) × 12 = 48/9 = 16/3 days Answer: A will take 16/3 days more.
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