Question
βPβ who is 20% more efficient than βQβ can
finish a work in 15 days. βPβ and βQβ start working together, but βQβ leaves after 6 days. The remaining work is completed by βPβ alone in βyβ days. Find the value of βyβ.Solution
ATQ,
Time taken by βQβ to complete the work = 1.2 Γ 15 = 18 days
Let the total work be 90 units
Efficiency of βPβ = 90/15 = 6 units/day
Efficiency of βQβ = 90/18 = 5 units/day
Work completed by βPβ and βQβ in 6 days = (6 + 5) Γ 6 = 66 units
Therefore, y = (90 β 66)/6 = 4
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