Question
The length of a rectangle is increased by 20% and the
width is decreased by 10%. What is the percentage change in the area of the rectangle?Solution
Let length = 100 and width = 100. New length = 120, new width = 90. Original area = 100 × 100 = 10000. New area = 120 × 90 = 10800. Percentage change = [(10800 - 10000) / 10000] × 100 = 8% increase. Answer: a) 8% increase.
More Quant Miscellaneous Questions
Evaluate: 360 ÷ [ {18 − (6×2)} × 5 ] + 72 − 33
(43)² - (28)² + (32)² = ?% of 2500
Evaluate:
√729 + √49 - √16 + 1/√64
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?62 of 8 - 320 ÷ 4 = ?3 + 200
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
60% of 120 – ?% of 64 = 20% of 200
35% of 840 + 162 = ? – 25% × 300
20% of 240 + 18% of 200 = ?
