Question
A man, a woman and a boy can do a work in 3, 2, 6 days
respectively. How many children were required with 1 man and 1 woman to complete the same work in 1/2 day?Solution
Work done by a man in 1/2 days = 1/6 part Work done by a woman in 1/2 days = 1/4 part Work done by a boy in 1/2 days = 1/12 part Let one man and one woman together can do a piece of work in 1/2 days = No. of x children required According to the question, 1/6 + 1/4 + 1/12 = 1 (2 + 3 + x )/12 = 1 5 + x = 12 x = 12 – 5 = 7 Hence, 7 boys will be required.
17 32 99 ? 1965 11784
...77 ? 190 257 331 412
...Given below are three numbers series I, II and II where each series contains a wrong (odd one out) term. The wrong number in series I, II and III are '...
91   93   97   100   ?   113
12 Â Â Â 11 Â Â Â Â 21 Â Â Â Â 62 Â Â Â Â ? Â Â Â Â Â 1234
13 15 ? 63 143 293
...102     153      306      765       ?     8032.5
...17 ? 33 44 57 72
...3 5 7 25 85 481
...1 4 13 46 ? 976
...
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