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ATQ, Let the total work be 560 units (LCM of 140, 112 and 80) Amount of work done by N alone in one day = 560/140 = 4 units Amount of work done by V alone in one day = 560/112 = 5 units Amount of work done by R alone in one day = 560/80 = 7 units Amount of work done by N, V and R together in 12 days = 12 × (4 + 5 + 7) = 192 units Amount of work done by V alone in 16 days = 16 × 5 = 80 units Remaining work = 560 – 192 – 80 = 288 units Time taken by V and R together to complete 288 units work = 288/(7 + 5) = 24 days So, the number days for which V worked = 12 + 16 + 24 = 52 days
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
? = 120% of (652 ÷ 132 ) + 33 × 8
?= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
√289 + √49 + 121 =?
Solve for ?.
∛21952 × 44 = ? × 14
Find the simplified value of the following expression:
72 + 132 X 4 - {232 + 172 - 402