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      Question

      'N,' 'V,' and 'R' have individual work completion times

      of 140 days, 112 days, and 80 days, respectively. They all started working together on a task, but after 12 days, 'N' left working, and 'R' also left the job 16 days before the task's completion. Calculate how many days 'V' worked on the task.
      A 45 days Correct Answer Incorrect Answer
      B 44 days Correct Answer Incorrect Answer
      C 35 days Correct Answer Incorrect Answer
      D 52 days Correct Answer Incorrect Answer
      E none of these Correct Answer Incorrect Answer

      Solution

      ATQ, ┬а Let the total work be 560 units (LCM of 140, 112 and 80) ┬а Amount of work done by N alone in one day = 560/140 = 4 units ┬а Amount of work done by V alone in one day = 560/112 = 5 units ┬а Amount of work done by R alone in one day = 560/80 = 7 units ┬а Amount of work done by N, V and R together in 12 days = 12 ├Ч (4 + 5 + 7) = 192 units ┬а Amount of work done by V alone in 16 days = 16 ├Ч 5 = 80 units ┬а Remaining work = 560 тАУ 192 тАУ 80 = 288 units ┬а Time taken by V and R together to complete 288 units work = 288/(7 + 5) = 24 days ┬а So, the number days for which V worked = 12 + 16 + 24 = 52 days

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