Question
βAβ alone can complete a work in 15 days. βBβ
alone can complete the same work in 18 days. If βAβ and βBβ work together for 6 days, then the remaining work can be completed by βAβ alone in how many days?Solution
Let the total amount of work = 90 units {LCM of 15 and 18} Then, efficiency of βAβ = 90/15 = 6 units/day Efficiency of βBβ = 90/18 = 5 units/day Combined efficiency of βAβ and βBβ = 6 + 5 = 11 units/day Work completed by βAβ and βBβ together in 6 days = 6 Γ 11 = 66 units Remaining work = 90 β 66 = 24 units Time taken by βAβ alone to complete the remaining work = 24/6 = 4 days
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