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Start learning 50% faster. Sign in nowLet the total amount of work = 90 units {LCM of 15 and 18} Then, efficiency of ‘A’ = 90/15 = 6 units/day Efficiency of ‘B’ = 90/18 = 5 units/day Combined efficiency of ‘A’ and ‘B’ = 6 + 5 = 11 units/day Work completed by ‘A’ and ‘B’ together in 6 days = 6 × 11 = 66 units Remaining work = 90 – 66 = 24 units Time taken by ‘A’ alone to complete the remaining work = 24/6 = 4 days
Statements: F % W, W © R, R @ M, M $ D
Conclusions:
 I.D @ R                               II.M $...
Statements:  P = Q < R < S; T ≥ U = S; V > T
Conclusions:
I. P > U
II. V = U
III. Q < V
Statements: P < Q = R ≥ S = T; R < U; R = W
Conclusion: I. W ≥ T II. U < P
Statements: J > K > M ≤ N < O; M > P > L
Conclusions:
I. J > L
II. P < O
III. J > O
In the following question the relationship between different elements are given in the statements followed by two conclusions I, and II. Read the state...
26. Statements:Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â T @ V % Z # D & B $ SÂ # E; W $ Z @ C
Conclusions :Â Â Â Â Â I. E @ ZÂ Â Â Â Â Â Â Â Â Â Â Â Â Â ...
Statement- 1 - 6# ≥ 9# ≥ 10# ≤ 5#
2 - 7* ≤ 10# ˃ 5* ≥ 6*
Conclusions:
1) 5# > 5*
2) 9# ˃ 6*
3) 7...
Statement:M = C ≥ A = V < Q = S
Conclusions:
I. M ≥ V
II. A < S
Statements: S > T > V ≤ W < X; V > P > U
Conclusions:
I. S > U
II. P < X
III. S > X
Statement: G ≤ L ≥ O ≥ W ≥ I < N
Conclusion: I. O > GÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. W < N
...