Question
βAβ and βBβ can do a piece of work in 25 days
and 30 days, respectively. If they started the work together and worked on it for 5 days, then find the time taken by βBβ alone to complete the remaining work.Solution
Let total amount of work be 150 units (LCM of 25 and 30). Efficiency of βAβ = 150/25 = 6 units/day Efficiency of βBβ = 150/30 = 5 units/day Amount of work done by βAβ and βBβ together in 5 days = (6 + 5) Γ 5 = 55 units Time taken by B to complete remaining work = (150 β 55)/5 = 19 days
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