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Start learning 50% faster. Sign in nowLet the total work be 50 units. {LCM (25 and 10)} So, efficiency of ‘A’ = (50/25) = 2 units/day So, efficiency of ‘B’ = (2 x 0.5) = 1 unit/day Efficiency of ‘B’ and ‘C’ together = (50/10) = 5 units/day So, efficiency of ‘C’ = 5 – 1 = 4 units/day So, time taken by ‘C’ to finish the work alone = (50/4) = 12.5 days
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