According to the question, Reena = 10 Teena = 10 + 20 Meena = 20 + 16 Work Done by (Reena + Teena) in 10 days = 2 × 10 = 20 units Work Done by (Teena + Meena) in 10 days = 3 × 20 = 60 units Total work (Finished till now) = 80 units Remaining Work = 120 – 80 = 40 units Here we find that Meena does remaining 40 units in 16 days Meena’s efficiency = work/day = 40/16 = 5/2 Therefore, time taken by Meena alone to complete the work = 120 × `2/5` = 48 days
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