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    Question

    Reena and Teena together can do a piece of work in 60

    days. Teena and Meena together can do it in 40 days. Reena starts the work and works on it for 10 days, then Teena takes up work for 30 days. Finally Meena finishes the work in 36 days. The number of days in which Meena alone can do the work where doing separately is
    A 54 days Correct Answer Incorrect Answer
    B 48 days Correct Answer Incorrect Answer
    C 24 days Correct Answer Incorrect Answer
    D 36 days Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    According to the question, Reena = 10 Teena = 10 + 20 Meena = 20 + 16 Work Done by (Reena + Teena) in 10 days = 2 × 10 = 20 units Work Done by (Teena + Meena) in 10 days = 3 × 20 = 60 units Total work (Finished till now) = 80 units Remaining Work = 120 – 80 = 40 units Here we find that Meena does remaining 40 units in 16 days Meena’s efficiency = work/day = 40/16 = 5/2 Therefore, time taken by Meena alone to complete the work = 120 × `2/5`   = 48 days

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