Question
A and B together can complete a piece of
work in 66 days while B and C together can complete the same work in 50 days. All of three together can complete 80% of the whole work in 26.4 days then find the time taken by A and C together to complete the whole work. Note: You have to find approx. valueSolution
Time taken by A, B and C together to complete the whole work = 26.4/0.80 = 33 days
Let total amount of work = 1650 (LCM of 66, 50 and 33)
Efficiency of (A + B) = 1650/66 = 25 units per day
Efficiency of (B + C) = 1650/50 = 33 units per day
Efficiency of (A + B + C) = 1650/33 = 50 units per day
Efficiency of A = 50 – 33 = 17 units per day
Efficiency of C = 50 – 25 = 25 units per day
Desired time = 1650/42 = 39.3 days = 39 days
More Time and work Questions
The value of [(3√2+2) × (3√2-2)] of 13 + 15 is:
136% of 560 - 2/7 of 630 + 45% of 420 =?
Simplify the following expressionÂ
Â
?% of 18% of 2600 = 234
- Evaluate: 156 ÷ 12 × 4 + 180 – 40% of 350
60 = (? x 10 + 250)/5
1360 ÷ 8 + 490 ÷ √49 + ? = 150 × 2

What will come in the place of question mark (?) in the given expression?
30% of 50% of 1200 = 18/11 × ?