Question
Walking at (8/9) of his usual pace, a person reaches his friend’s house 18 minutes late. Find the time he usually takes to cover the distance.
Solution
ATQ, When distance is constant, Time ∝ (1 / Speed) Ratio of usual time to new time = 8 : 9 Let usual time = 8t and new time = 9t. 9t – 8t = 18 ⇒ t = 18 Usual time = 8t = 8 × 18 = 144 minutes
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