Question
Two men start together to walk a certain distance, one
at 4 km/h and another at 3 km/h. The former arrives half an hour before the latter. Find the distance.Solution
Time = Distance / SpeedSo, Time taken by first man = D / 4
Time taken by second man = D / 3
Second man takes 0.5 hour more than the first man: D/3 – D/4 = 0.5
(4D − 3D)/12 = 0.5 ⇒D/12 = 0.5 ⇒D = 0.5 × 12 = 6
The distance is 6 km.
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AB`->` CD
AF`->` D
DE`->` F
C`->` G
F`->` E
G`->` A
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