Question
A person travels from city ‘X’ to city ‘Y’ covering
(1/4)th of the total distance in 2 hours and the remaining in 6 hours. If he returns to city ‘X’ from city ‘Y’ in 8 hours, then find his average speed for the entire journey given that the distance between city ‘X’ and city ‘Y’ is 64 km.Solution
ATQ,
Average speed = total distance covered ÷ total time taken
Total time taken = 2 + 6 + 8 = 16 hours
Total distance covered = 64 × 2 = 128 km.
Required average speed = 128/16 = 8 km/h
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